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Question: Answered & Verified by Expert
The value of $g$ on the earth's surface is $980 \mathrm{~cm} / \mathrm{sec}^2$. Its value at a height of $64 \mathrm{~km}$ from the earth's surface is
PhysicsGravitationJEE Main
Options:
  • A $960.40 \mathrm{~cm} / \mathrm{sec}^2$
  • B $984.90 \mathrm{~cm} / \mathrm{sec}^2$
  • C $982.45 \mathrm{~cm} / \mathrm{sec}^2$
  • D $977.55 \mathrm{~cm} / \mathrm{sec}^2$
    (Radius of the earth $R=6400$ kilometers)
Solution:
1573 Upvotes Verified Answer
The correct answer is: $960.40 \mathrm{~cm} / \mathrm{sec}^2$
$\frac{g^{\prime}}{g}=\left(\frac{R}{R+h}\right)^2=\left(\frac{6400}{6400+64}\right)^2 \Rightarrow g^{\prime}=960.40 \mathrm{~cm} / \mathrm{s}^2$

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