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Question: Answered & Verified by Expert
The value of $\Delta H$ for cooling 2 mole of an ideal monoatomic gas from $225^{\circ} \mathrm{C}$ to $125^{\circ} \mathrm{C}$ at constant pressure will be [given $\left.C_{p}=\frac{5}{2} R\right]$
ChemistryThermodynamics (C)WBJEEWBJEE 2014
Options:
  • A $250 \mathrm{R}$
  • B $-500 R$
  • C $500 \mathrm{R}$
  • D $-250 R$
Solution:
1578 Upvotes Verified Answer
The correct answer is: $-500 R$
$\Delta H=-n C_{p} \Delta T=-2 \times \frac{5}{2} R(225-125)$
$$
=-5 R(100)=-500 R
$$

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