The value of \(\int_{-2}^2(x \cos x+\sin x+1) d x\) is, 2, 0, -2, 4

The value of \(\int_{-2}^2(x \cos x+\sin x+1) d x\) is

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The value of \(\int_{-2}^2(x \cos x+\sin x+1) d x\) is

MathematicsDefinite IntegrationJEE Main

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The correct answer is: 4

Hints: \(\int_{-2}^2(x \cos x+\sin x+1) d x=\int_{-2}^2 d x=4\)

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