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The value of $k$ for which the lines $2 x+3 y+a=0$ and $5 x+k y+a=0$ represent family of parallel lines is
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The correct answer is:
$7.5$
$2 \mathrm{x}+3 \mathrm{y}+\mathrm{a}=0$ or $\mathrm{y}=\frac{-2}{3} \mathrm{x}-\frac{\mathrm{a}}{3}$
Slope $=\frac{-2}{3}$
$5 x+k y+a=0$ or $y=\frac{-5}{k} x \frac{-a}{5}$
Slope $=\frac{-5}{\mathrm{k}}$
lines are parallel $\frac{-2}{3}=\frac{-5}{\mathrm{k}}$
$\mathrm{k}=\frac{15}{2}=7.5$
Slope $=\frac{-2}{3}$
$5 x+k y+a=0$ or $y=\frac{-5}{k} x \frac{-a}{5}$
Slope $=\frac{-5}{\mathrm{k}}$
lines are parallel $\frac{-2}{3}=\frac{-5}{\mathrm{k}}$
$\mathrm{k}=\frac{15}{2}=7.5$
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