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Question: Answered & Verified by Expert
The value of limx0secx+tanx1x is equal to
MathematicsLimitsJEE Main
Options:
  • A e
  • B e2
  • C e-1
  • D 1
Solution:
2169 Upvotes Verified Answer
The correct answer is: e
limx0secx+tanx1x  (1 form)
=elimx01xsecx+tanx-1=elimx01+sinx-cosxxcosx=elimx0cosx+sinx-xsinx+cosx by L'Hospital rule
=e1+00+1=e

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