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Question: Answered & Verified by Expert
The value of limncosx2cosx4cosx8...cosx2n+1 is equal to
MathematicsLimitsJEE Main
Options:
  • A xsinx
  • B sinxx
  • C 0
  • D None of these
Solution:
1895 Upvotes Verified Answer
The correct answer is: sinxx
Let, L=limncosx2cosx22cosx23..cosx2n+1
=limn12sinx2n+1cosx2cosx2n2sinx2n+1cosx2n+1
=limn122sinx2n+1cosx22cosx2nsinx2n
=limn12n+1sinx2n+12cosx2sinx2=limnsinx2n+1sinx2n+1
=sinxxlimnx2n+1sinx2n+1=sinxx

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