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Question: Answered & Verified by Expert
The value of limx01-cos3xsin2xcosx is equal to
MathematicsLimitsJEE Main
Solution:
1477 Upvotes Verified Answer
The correct answer is: 1.5
limx01-cos3xsin2xcosx
=limx01-cosx1+cos2x+cosxsin2xcosx
=limx02sin2x21+cos2x+cosx2sinx2cosx22cosx
= lim x0 1 2 1+ cos 2 x+cosx cos x 2 2 cosx
=1231=32

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