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Question: Answered & Verified by Expert
The value of limx0cosx+sinx1x is equal to (take e=2.71)
MathematicsLimitsJEE Main
Solution:
1804 Upvotes Verified Answer
The correct answer is: 2.71

limxafxϕx=elimxaϕxfx-1 as fx1 & ϕx as xa

So, limx0cosx+sinx1x=elimx01xcosx+sinx-1
=elimx0-sinx+cosx1=e

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