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Question: Answered & Verified by Expert
The value of limx0x6000-sin x6000x2sinx6000 is
MathematicsLimitsJEE Main
Options:
  • A 1000
  • B 100
  • C 1100
  • D 1010
Solution:
2346 Upvotes Verified Answer
The correct answer is: 1000
limx0x6000-sinx6000x2sinx6000x6000.x600000

limx0x6000-sinx6000x6002

= -limx0sinx6000-x6000x6002

=-limx0sinxx6000-1x2

=-limx06000sinxx5999xcosx-sinxx22x (By L-Hospital Rule)

=-60002limx0xcosx-sinxx3

 
=-3000 limx0cosx-x sinx-cosx3x2 

=1000

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