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Question: Answered & Verified by Expert
The value of limx2πcosx-cosxcosx1-cosx+lncosx is equal to
MathematicsLimitsJEE Main
Solution:
1610 Upvotes Verified Answer
The correct answer is: 2
Let, L=limx2πcosx-(cosx)cosx1-cosx+lncosx
Putting cosx=t , we get,
L=limt1t-tt1-t+lnt
Now by L-Hospital rule
L=limt11-tt(1+lnt)-1+1t
Again by L-Hospital rule
=limt1-tt1t-tt1+lnt2-1t2=2

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