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Question: Answered & Verified by Expert
The value of $\lim _{x \rightarrow \infty}\left(\frac{x^{2}-2 x+1}{x^{2}-4 x+2}\right)^{x}$ is
MathematicsLimitsJEE Main
Options:
  • A $e^{2}$
  • B $e^{-2}$
  • C $e^{6}$
  • D None of these
Solution:
2908 Upvotes Verified Answer
The correct answer is: $e^{2}$
$\begin{aligned} & \lim _{x \rightarrow \infty}\left(\frac{x^{2}-2 x+1}{x^{2}-4 x+2}\right)^{x} \\ &=\lim _{x \rightarrow \infty}\left(1+\frac{2 x-1}{x^{2}-4 x+2}\right)^{x} \\ &=e^{\lim _{x \rightarrow-\infty}\left(\frac{x(2 x-1)}{x^{2}-4 x+2}\right)}=e^{2} \end{aligned}$

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