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The value of $n$ in the molecular formula $\mathrm{Be}_n \mathrm{Al}_2 \mathrm{Si}_6 \mathrm{O}_{18}$ is
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For $\mathrm{Be}_n \mathrm{Al}_2 \mathrm{Si}_6 \mathrm{O}_{18} \quad n=3$
$$
2 n+6+24-36=0 \quad n=3
$$
Chemical bonding
Basic application
II
$$
2 n+6+24-36=0 \quad n=3
$$
Chemical bonding
Basic application
II
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