The value of β of a transistor is 19. The value of α will be, 0 . 93, 0 . 98, 0 . 99, 0 . 95

I E = I B + I C ⇒ I E I C = I B I C + 1 ⇒ 1 α = 1 β + 1 = 1 19 + 1 ⇒ 1 α = 20 19 ⇒ α = 19 20 = 0.95

The value of β of a transistor is 19. The value of α will be

Question: Answered & Verified by Expert

The value of

β

of a transistor is 19. The value of

α

will be

PhysicsSemiconductorsNEET

Options:

Solution:

2604 Upvotes Verified Answer

The correct answer is:

0.95

I_{E} = I_{B} + I_{C}

\Rightarrow \frac{I_{E}}{I_{C}} = \frac{I_{B}}{I_{C}} + 1

\Rightarrow \frac{1}{α} = \frac{1}{β} + 1 = \frac{1}{19} + 1

\Rightarrow \frac{1}{α} = \frac{20}{19}

\Rightarrow α = \frac{19}{20} = 0.95

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