Search any question & find its solution
Question:
Answered & Verified by Expert
The value of $\sin ^{2} 51^{\circ}+\sin ^{2} 39^{\circ}$ is
Options:
Solution:
1151 Upvotes
Verified Answer
The correct answer is:
1
We have,
$\begin{aligned}
&\sin ^{2} 51^{\circ}+\sin ^{2} 39^{\circ} \\
&\sin ^{2} 51^{\circ}+\sin ^{2}\left(90^{\circ}-51^{\circ}\right) \\
&\sin ^{2} 51^{\circ}+\cos ^{2} 51^{\circ}=1
\end{aligned}$
$\begin{aligned}
&\sin ^{2} 51^{\circ}+\sin ^{2} 39^{\circ} \\
&\sin ^{2} 51^{\circ}+\sin ^{2}\left(90^{\circ}-51^{\circ}\right) \\
&\sin ^{2} 51^{\circ}+\cos ^{2} 51^{\circ}=1
\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.