Search any question & find its solution
Question:
Answered & Verified by Expert
The value of $\sin 600^{\circ} \cos 330^{\circ}+\cos 120^{\circ} \sin 150^{\circ}$ is
Options:
Solution:
1570 Upvotes
Verified Answer
The correct answer is:
-1
$\text { } \begin{aligned}
\sin 600^{\circ} \cos 330^{\circ} & +\cos 120^{\circ} \sin 150^{\circ} \\
& =-\sin 60^{\circ} \cos 30^{\circ}-\sin 30^{\circ} \cos 60^{\circ} \\
= & -\left\{\sin \left(60^{\circ}+30^{\circ}\right)\right\}=-1 .
\end{aligned}$
\sin 600^{\circ} \cos 330^{\circ} & +\cos 120^{\circ} \sin 150^{\circ} \\
& =-\sin 60^{\circ} \cos 30^{\circ}-\sin 30^{\circ} \cos 60^{\circ} \\
= & -\left\{\sin \left(60^{\circ}+30^{\circ}\right)\right\}=-1 .
\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.