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The value of \( \tan \frac{\Pi}{8} \) is equal to
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The correct answer is:
\( \frac{1}{\sqrt{2}+1} \)
\( \tan \theta=\frac{\Pi}{8} \)
\( =\frac{\sin 2(\Pi / 8)}{1+\cos 2(\Pi / 8)} \)
\( =\frac{\sin (\Pi / 4)}{1+\cos (\Pi / 4)} \)
\( =\frac{1}{\sqrt{2}+1} \)
\( =\frac{\sin 2(\Pi / 8)}{1+\cos 2(\Pi / 8)} \)
\( =\frac{\sin (\Pi / 4)}{1+\cos (\Pi / 4)} \)
\( =\frac{1}{\sqrt{2}+1} \)
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