The value of the integral ∫ 0 8 x 2 x 2 - 8 x + 32 d x is equal to

Question

The value of the integral ∫ 0 8 x 2 x 2 - 8 x + 32 d x is equal to,

MARKS App · Accepted Answer

Let, I = ∫ 0 8 x 2 x x - 8 + 32 d x So, I = ∫ 0 8 8 - x 2 - x 8 - x + 32 d x ∫ a b f x d x = ∫ a b f a + b - x d x Adding both equations, we get, 2 I = ∫ 0 8 2 x 2 - 8 x + 32 x 2 - 8 x + 32 d x = 16 ⇒ I = 8

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