The value of the integral ∫ - 1 1 log x + x 2 + 1 d x is:

Question

The value of the integral ∫ - 1 1 log x + x 2 + 1 d x is:, 2, 0, - 1, 1

MARKS App · Accepted Answer

Let I = ∫ - 1 1 log x + x 2 + 1 d x Consider f x = log x + x 2 + 1 Now, f - x = log - x + 1 + x 2 ⇒ f - x = - log x + 1 + x 2 ⇒ f - x = - f x So, f x is an odd function. ∴ I = 0

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