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The values of $x$ and $y$ for which the numbers $3+i x^2 y$ and $x^2+y+4 i$ are conjugate complex can be
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The correct answer is:
$(-2,-1)$ or $(2,-1)$
According to condition, $\quad 3-i x^2 y=x^2+y+4 i$
$\begin{aligned}& \Rightarrow x^2+y=3 \text { and } x^2 y=-4 \Rightarrow x= \pm 2, y=-1 \\& \Rightarrow(x, y)=(2,-1) \text { or }(-2,-1)\end{aligned}$
$\begin{aligned}& \Rightarrow x^2+y=3 \text { and } x^2 y=-4 \Rightarrow x= \pm 2, y=-1 \\& \Rightarrow(x, y)=(2,-1) \text { or }(-2,-1)\end{aligned}$
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