The vapour density of a volatile chloride of a metal is 95 and the specific heat of the metal is 0.13 Cal/g. The exact atomic weight of metal is

Question

The vapour density of a volatile chloride of a metal is 95 and the specific heat of the metal is 0.13 Cal/g. The exact atomic weight of metal is, 50, 49.23, 19.692, 98.12

MARKS App · Accepted Answer

Molecular weight = 2 × V . D . = 2 × 95 = 190 Approx atomic weight = 6.4 s p e c i f i c h e a t = 6.4 0.13 = 49.23 Suppose the formula of metal chloride = M C l X Molecular weight = 49.23 + 35.5 X = 190 So, X = 4(Nearest whole no.) Formula is MCl 4 mol . wt .= at . wt . of metal exact + 35.5 × 4 190 − 140 = at .wt . at . wt .= 50

Search any question & find its solution

Looking for more such questions to practice?