Search any question & find its solution
Question:
Answered & Verified by Expert
The vapour pressure of pure $\mathrm{CHCl}_3$ and $\mathrm{CH}_2 \mathrm{Cl}_2$ are 200 and 41.5 atm respectively. The weight of $\mathrm{CHCl}_3$ and $\mathrm{CH}_2 \mathrm{Cl}_2$ are $11.9 \mathrm{~g}$ and $17 \mathrm{~g}$ respectively in a solution. The vapour pressure of solution (in atm) will be
Options:
Solution:
2189 Upvotes
Verified Answer
The correct answer is:
$94.3$
$\begin{aligned} & \text { (c) }: p_{\mathrm{CHCl}_3}^{\mathrm{o}}=200 \mathrm{~atm} ; p_{\mathrm{CH}_2 \mathrm{Cl}_2}^{\mathrm{o}}=41.5 \mathrm{~atm} \\ & n_{\mathrm{CHCl}}=11.9 / 119.5=0.1, n_{\mathrm{CH}_2 \mathrm{Cl}_2}=17 / 85=0.2 \\ & P_T=p_A^{\mathrm{o}} x_A+p_B^{\mathrm{o}} x_B \\ & =200 \times(0.1 / 0.3)+41.5 \times(0.2 / 0.3)=94.3 \mathrm{~atm}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.