The vapour pressure of pure liquid A decreases from 0.80 a t m to 0.6 a t m on mixing a non-volatile solute B to liquide A . The mole fraction of B in the solution is

Question

The vapour pressure of pure liquid A decreases from 0.80 a t m to 0.6 a t m on mixing a non-volatile solute B to liquide A . The mole fraction of B in the solution is, 0.25, 1, 0.50, 0.75

MARKS App · Accepted Answer

According to Raoult’s Law P 0 - P s P 0 = x B (Mole fraction of solute) x B = 0.8 - 0.6 0.8 = 0.25 .

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