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The variation of electric field along the $Z$-axis due to a uniformly charged circular ring of radius ' $a$ ' in $X Y$ plane is shown in the figure. The value of coordinate $M$ will be
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1627 Upvotes
Verified Answer
The correct answer is:
$\frac{1}{\sqrt{2}}$
For $E_{z}$ to be maximum,
$$
\frac{d E_{z}}{d z}=0 \quad \therefore z=a / \sqrt{2} \quad \text { or } \frac{z}{a}=\frac{1}{\sqrt{2}}
$$
$$
\frac{d E_{z}}{d z}=0 \quad \therefore z=a / \sqrt{2} \quad \text { or } \frac{z}{a}=\frac{1}{\sqrt{2}}
$$
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