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The variation of terminal potential difference \( (V) \) with current flowing through as cell is as
shown
The emf and internal resistance of the cell are
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shown
The emf and internal resistance of the cell are
Solution:
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The correct answer is:
\( 3 \mathrm{~V}, 0.5 \Omega \)
(D)
$V=E-$ Ir
This is the form of $: y=m x+c$
When $I=0, V=E=3 \mathrm{~V}$
When $V=0, r=\frac{E}{1}=\frac{3}{6}=0.5 \Omega$
$V=E-$ Ir
This is the form of $: y=m x+c$
When $I=0, V=E=3 \mathrm{~V}$
When $V=0, r=\frac{E}{1}=\frac{3}{6}=0.5 \Omega$
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