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Question: Answered & Verified by Expert
The variation of the potential energy of harmonic oscillator is as shown in the figure. The spring constant is

PhysicsOscillationsNEET
Options:
  • A 1×102 N m-1
  • B 150 N m-1
  • C 66.7 N m-1
  • D 3×102 N m-1
Solution:
1043 Upvotes Verified Answer
The correct answer is: 150 N m-1
Total potential energy =0.04 J
Resting potential energy =0.01 J
Maximum kinetic energy =0.04-0.01

=0.03 J
  0.03 J=12 m ω2 A2=12 kA2

  0.03   =12×k×2010002

  k=0.06×2500 N m-1=150 N m-1

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