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Question: Answered & Verified by Expert
The vector equation of the plane r=2i^+k^+λi^+μi^+2j^-3k^ in scalar product from is r.3i^+2k^=α , then α=
MathematicsVector AlgebraMHT CETMHT CET 2019 (Shift 1)
Options:
  • A 2
  • B 3
  • C 1
  • D 0
Solution:
2390 Upvotes Verified Answer
The correct answer is: 2
Given, equation of plane
r=2i^+k^+λi^+μi^+2j^-3k^     (i)
Here , plane (i) passing through a (let) =2i^+k^ and parallel to vector b (let) =i^ and c=i^+2j^-3k^
We know that equation of plane passing through a point a and parallel to non-parallel vectors b and c is r.b×c=a.b×c=abc
Now, abc=20110012-3
=20-0+12-0=2
and b×c=i^j^k^10012-3=3i^+2k^
r3i^+2k^=2
Therefore , α=2

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