Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The velocity of a particle is v=v0+gt+Ft2 m s-1. Its position is x=0 at t=0 ; then its displacement after time (t=1 s) is :
PhysicsMotion In One DimensionJEE MainJEE Main 2021 (17 Mar Shift 2)
Options:
  • A v0+g+F
  • B v0+g2+F3
  • C v0+g2+F
  • D v0+2g+3F
Solution:
1424 Upvotes Verified Answer
The correct answer is: v0+g2+F3

v=v0+gt+Ft2

dsdt=v0+gt+Ft2

ds=01v0+gt+Ft2dt

s=v0t+gt22+Ft3301

s=v0+g2+F3

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.