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The velocity of kerosene oil in a horizontal pipe is $5 \mathrm{~m} / \mathrm{s}$. If $g=10 \mathrm{~m} / \mathrm{s}^2$ then the velocity head of oil will be
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$1.25 \mathrm{~m}$
Velocity head $h=\frac{v^2}{2 g}=\frac{(5)^2}{2 \times 10}=1.25 \mathrm{~m}$
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