The velocity-time graph of a particle moving along a straight line is as shown in the diagram. The rate of acceleration and retardation is constant and is equal to 5 m s - 2 . If the average velocity during the motion is 20 m s - 1 , then the maximum velocity of the particle is

Question

The velocity-time graph of a particle moving along a straight line is as shown in the diagram. The rate of acceleration and retardation is constant and is equal to 5 m s - 2 . If the average velocity during the motion is 20 m s - 1 , then the maximum velocity of the particle is, 20 m s - 1, 25 m s - 1, 30 m s - 1, 40 m s - 1

MARKS App · Accepted Answer

Average speed = 20 m s - 1 Total distance Total time = 2 0 ⇒ Area of graph 2 0 + t = 2 0 ⇒ 1 2 2 0 + t + 2 0 - t × 5 t = 2 0 2 0 + t ⇒ t = 5 s Maximum velocity = 5 t = 5 × 5 = 25 m s - 1

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