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Question: Answered & Verified by Expert
The velocity-time graph of a particle of mass 10 kg is shown in the figure. The net work done on the particle in the first two seconds of the motion is

PhysicsWork Power EnergyJEE Main
Options:
  • A -9300 J
  • B 12000 J
  • C -4500 J
  • D -12000 J
Solution:
2598 Upvotes Verified Answer
The correct answer is: -4500 J
v=-5t+50

vat t=2=40

∆ K.E.=W.D. =12402-502×10

=-4500 J

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