The vertex of the parabola $y^2+6 x-2 y+13=0$ is $\begin{aligned} & (y-1)^2=-6 x-12 \ & (y-1)^2=-6(x+2)=4\left(\frac{-6}{4}\right)(x+2) \ & \text { Vertex } \rightarrow(-2,1) \end{aligned}$

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The vertex of the parabola $y^2+6 x-2 y+13=0$ is $\begin{aligned} & (y-1)^2=-6 x-12 \ & (y-1)^2=-6(x+2)=4\left(\frac{-6}{4}\right)(x+2) \ & \text { Vertex } \rightarrow(-2,1) \end{aligned}$, $(1,-1)$, $(-2,1)$, $\left(\frac{3}{2}, 1\right)$, $\left(-\frac{7}{2}, 1\right)$

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