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Question: Answered & Verified by Expert
The Vividh Bharti Station of All India Radio, Delhi, broadcasts on a frequency of $1,368 \mathrm{kHz}$ (Kilohertz). Calculate the wavelength $(\lambda)$ of the electromagnetic radiation emitted by transmitter. Which part of the electromagnetic spectrum does it belong to?
ChemistryStructure of AtomJIPMERJIPMER 2015
Options:
  • A 319.4 m and X-rays
  • B 319.4 m and radiowave
  • C 219.3 m and microwave
  • D 219.3 m and radiowave
Solution:
2577 Upvotes Verified Answer
The correct answer is: 219.3 m and radiowave
$v=1,368 \times 10^3 \mathrm{~Hz}$
$\lambda=\frac{C}{v}=\frac{3 \times 10^8 \mathrm{~m} / \mathrm{s}}{1368 \times 10^3 \mathrm{~s}^{-1}}=219.3 \mathrm{~m}$
The range of wavelength of radiowaves is 100 m to radiation is 10000 m .

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