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Question: Answered & Verified by Expert

The volume in mL of 0.125 M AgNO3 required to quantitatively precipitate chloride ions in 0.3g of CoNH36Cl3 is __________.
CoNH36MCl3=267.46g/mol
AgNOM3=169.87g/mol

Report the nearest integer as the answer.

ChemistrySome Basic Concepts of ChemistryJEE MainJEE Main 2020 (08 Jan Shift 1)
Solution:
1180 Upvotes Verified Answer
The correct answer is: 27
ML6Cl30.3g+3AgNO3Vml,0.125M3AgCl
0.3267.46×3=0.125×V×10-3
Or, V=0.3×3×1000267.46×0.125=26.92ml

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