The volume (in $ \mathrm{mL} $ ) of $ 0.1 \mathrm{~N} \mathrm{NaOH} $ required to neutralise $ 10 \mathrm{~mL} $ of $ 0.1 \mathrm{~N} $ phosphinic acid is

Question

The volume (in $ \mathrm{mL} $ ) of $ 0.1 \mathrm{~N} \mathrm{NaOH} $ required to neutralise $ 10 \mathrm{~mL} $ of $ 0.1 \mathrm{~N} $ phosphinic acid is,

MARKS App · Accepted Answer

Phosphinic acid is hypo phosphorous acid H 3 PO 2 . NaOH + H 3 PO 2 → NaH 2 PO 2 + H 2 O For neutrization N 1 V 1 acid = N 2 V 2 base 0 . 1 × 10 = 0 . 1 × V mL NaOH V NaOH = 10 mL

Search any question & find its solution

Looking for more such questions to practice?