Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The volume of a cube is increasing at the rate of 9 cm3/sec. The rate (in cm2/sec) at which the surface area is increasing when the edge of the cube is 9 cm, is
MathematicsApplication of DerivativesJEE Main
Options:
  • A 1
  • B 2
  • C 3
  • D 4
Solution:
2130 Upvotes Verified Answer
The correct answer is: 4
Let, length of the edge of the cube is a,  volume is V and surface area is S, then
V=a3dVdt=3a2dadt
dadt=3a21
Now, S=6a2dSdt=12adadt
dSdt=129×392=369=4cm2/sec.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.