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Question: Answered & Verified by Expert
The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is :
PhysicsKinetic Theory of GasesJEE MainJEE Main 2021 (16 Mar Shift 1)
Options:
  • A 88RTV
  • B 3RTV
  • C 52RTV
  • D 4RTV
Solution:
2218 Upvotes Verified Answer
The correct answer is: 52RTV

PV=n1+n2+n3RT

P×V=1632+2828+4444RT

PV=12+1+1RT

P=52RTV

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