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The volume vs. temperature graph of I mole of an ideal gas is given below. The pressure of the gas (in atm) at $X, Y$ and $Z$, respectively, are
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Verified Answer
The correct answer is:
$0.328,0.820,0.820$
Using ideal gas equation, $\mathrm{PV}=\mathrm{nRT}$
$$
\begin{array}{l}
\mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{V}} ; \quad \mathrm{P}_{\mathrm{x}}=\frac{1 \times 0.082 \times 200}{50}=0.328 \mathrm{~atm} \\
\mathrm{P}_{\mathrm{y}}=\frac{1 \times 0.082 \times 500}{50}=0.820 \mathrm{~atm} \mathrm{P}_{x}=\frac{1 \times 0.082 \times 200}{50}=0.820 \mathrm{~atm}
\end{array}
$$
$$
\begin{array}{l}
\mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{V}} ; \quad \mathrm{P}_{\mathrm{x}}=\frac{1 \times 0.082 \times 200}{50}=0.328 \mathrm{~atm} \\
\mathrm{P}_{\mathrm{y}}=\frac{1 \times 0.082 \times 500}{50}=0.820 \mathrm{~atm} \mathrm{P}_{x}=\frac{1 \times 0.082 \times 200}{50}=0.820 \mathrm{~atm}
\end{array}
$$
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