Search any question & find its solution
Question:
Answered & Verified by Expert
The v-t graph of a moving object is given in the figure. The maximum acceleration is:
Options:
Solution:
2044 Upvotes
Verified Answer
The correct answer is:
$6 \mathrm{~cm} / \mathrm{sec}^2$
Acceleration in the 1st part,
$\begin{aligned} & a_1=\frac{20-0}{20}=1 \mathrm{~cm} / \mathrm{s}^2 \\ & a_2=0 \\ & a_3=\frac{80-20}{40-30}=\frac{60}{10}=6 \mathrm{~cm} / \mathrm{s}^2 \\ & a_4=\frac{80-0}{80-40}=\frac{80}{40}=2 \mathrm{~cm} / \mathrm{s}^2\end{aligned}$
Max. acceleration is $6 \mathrm{~cm} / \mathrm{s}^2$
$\begin{aligned} & a_1=\frac{20-0}{20}=1 \mathrm{~cm} / \mathrm{s}^2 \\ & a_2=0 \\ & a_3=\frac{80-20}{40-30}=\frac{60}{10}=6 \mathrm{~cm} / \mathrm{s}^2 \\ & a_4=\frac{80-0}{80-40}=\frac{80}{40}=2 \mathrm{~cm} / \mathrm{s}^2\end{aligned}$
Max. acceleration is $6 \mathrm{~cm} / \mathrm{s}^2$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.