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The Wheatstone bridge shown in the diagram is balanced. If $\mathrm{P}_3$ is the power dissipated by $\mathrm{R}_3$ and $\mathrm{P}_1$ is the power dissipated by $R_1$, then the ratio $\frac{\mathrm{P}_3}{\mathrm{P}_1}$ is
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The correct answer is:
$\frac{\mathrm{K}}{\mathrm{L}}$
From wheat stone bridge, we have
$\begin{aligned} & \frac{R_1}{R_3}=\frac{L}{K} \\ & P=I^2 R \\ & \frac{P_3}{P_1}=\frac{I^2 R_3}{I^2 R_1}=\frac{K}{L}\end{aligned}$
$\begin{aligned} & \frac{R_1}{R_3}=\frac{L}{K} \\ & P=I^2 R \\ & \frac{P_3}{P_1}=\frac{I^2 R_3}{I^2 R_1}=\frac{K}{L}\end{aligned}$
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