Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The wheel of a toy car rotates about an axis on the rough surface. Its angular frequency slows down from 400 rps to 200 rps in 2 s. Then its angular retardation in rad s-is
PhysicsLaws of MotionNEET
Options:
  • A 200 π
  • B 100 π
  • C 400 π
  • D None of these
Solution:
1183 Upvotes Verified Answer
The correct answer is: 200 π
Given, ω1=2π×(400) rad s-1

ω2=2π×(200) rad s-1

α = 2 π 4 0 0 - 2 0 0 2 = 2 0 0 π radions    α  is the retardation.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.