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The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of $20 \mathrm{~m}$ is
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Verified Answer
The correct answer is:
$200 \mathrm{~J}$
Word done $W=$ Area ABCEFDA $=$ Area $\mathrm{ABCD}+$ Area CEFD
$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$
$=125+75=200 \mathrm{~J}$
$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$
$=125+75=200 \mathrm{~J}$
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