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The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is
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200 J
Work done $W=$ Area $A B C D E F G A$
$=$ Area $A B C D G+$ Area $D E F G$
$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$
$=125+75=200 \mathrm{~J}$
$=$ Area $A B C D G+$ Area $D E F G$
$=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$
$=125+75=200 \mathrm{~J}$
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