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The work done by an uniform magnetic field, on a moving charge is
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zero because $\vec{F}$ acts perpendicular to $\overrightarrow{\mathrm{v}}$
Force on moving charge while moving in magnetic field is; $\overrightarrow{\mathrm{F}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})$ where $\overrightarrow{\mathrm{F}}$ is perpendicular to $\overrightarrow{\mathrm{V}}$.
Work done/sec $=\overrightarrow{\mathrm{F}} \cdot \overrightarrow{\mathrm{v}}=\mathrm{Fv} \cos 90^{\circ}=0$
Work done/sec $=\overrightarrow{\mathrm{F}} \cdot \overrightarrow{\mathrm{v}}=\mathrm{Fv} \cos 90^{\circ}=0$
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