The work done in an open vessel at 300 K , when 112 g iron reacts with dil. HCl is ( R = 2 cal mol - 1 K - 1 )

Question

The work done in an open vessel at 300 K , when 112 g iron reacts with dil. HCl is ( R = 2 cal mol - 1 K - 1 ), 1200 cal, 600 cal, 300 cal, 200 cal

MARKS App · Accepted Answer

Fe + 2 HCl → FeCl 2 + H 2 1 mol 1 mol 1 1 2 5 6 = 2 mol 2 mol Now, V 2 = V H 2 and V 1 = 0 (For solid + aqueous state) Work done = - p ext Δ V = − Δ ( P V ) = − n H 2 R T = - 2 × 2 × 3 0 0 = - 1200 cals (Work of expansion)

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