The work done in placing the dielectric slab inside one of the capacitors as shown in the diagram.

Question

The work done in placing the dielectric slab inside one of the capacitors as shown in the diagram., C V 2 2 K – 1 K + 1, C V 2 4 K – 1 K + 1, C V 2 4 K + 1 K – 1, C V 2 2 K + 1 K – 1

MARKS App · Accepted Answer

U i = 1 2 C / 2 V 2 = C V 2 4 U f = 1 2 C × K C C + K C V 2 = K C V 2 2 1 + K W = Δ U = U f – U i = K C V 2 2 1 + K - C V 2 4 = C V 2 2 K 1 + K – 1 2 = C V 2 2 2 K – 1 – K 2 1 + K = C V 2 4 K – 1 K + 1

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