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The work function for caesium atom is 1.9 eV. If the caesium element is irradiated with a wavelength 500 nm, calculate (i) the kinetic energy and (ii) the velocity of the ejected photoelectron.
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The correct answer is:
(i)9.29 ×10–20J and (ii) 4.516 × 105ms–1
Correct Option is : (C)
(i)9.29 ×10–20J and (ii) 4.516 × 105ms–1
(i)9.29 ×10–20J and (ii) 4.516 × 105ms–1
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