Given that, $2 eV \le \varphi \le 5 eV$

Wavelength corresponding to minimum and maximum values of work function are

${\lambda }_{max}=\frac{hc}{E}=\frac{4\times {10}^{-15}\times 3\times {10}^8}{2}$

$= 6\times {10}^{-7}m=600 nm$

And ${\lambda }_{min}=\frac{hc}{E}=\frac{4\times {10}^{-15}\times 3\times {10}^8}{5}$

$= 2.4\times {10}^{-7}m=240 nm$

Clearly wavelength range would be $240\le \lambda \le 600$

Thus, wavelength 650 nm is not suitable for photoelectric effect.