Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The x-t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t=43 s is:

PhysicsOscillationsJEE Main
Options:
  • A 332π2 cm s-2
  • B -π232 cm s-2
  • C π232 cm s-2
  • D -332π2 cm s-2
Solution:
2176 Upvotes Verified Answer
The correct answer is: -332π2 cm s-2
x=sin2π8t
a=-ω2x=-2π8×2π8×sin2π8×43
a=π216×32=-3π232 cm s-2

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.