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Question: Answered & Verified by Expert
There are 10 points in a plane, of which no three points are collinear except 4 . Then, the number of distinct triangles that can be formed by joining any three points of these ten points, such that at least one of the vertices of every triangle formed is from the given 4 collinear points is
MathematicsPermutation CombinationTS EAMCETTS EAMCET 2023 (14 May Shift 1)
Options:
  • A $80$
  • B $100$
  • C $96$
  • D $116$
Solution:
1909 Upvotes Verified Answer
The correct answer is: $96$
Number of required triangles:
(Select 1 point from 4 collinear and 2 from remaining 6 ) OR (select 2 from collinear points \& 1 from remaining 6 )
$$
\begin{aligned}
& =\left({ }^4 C_1 \times{ }^6 C_2\right)+\left({ }^4 C_2 \times{ }^6 C_1\right) \\
& =(4 \times 15)+(6 \times 6)=96
\end{aligned}
$$

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