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There are $n$ white and $n$ black balls marked $1,2,3, \ldots . n$. The number of ways in which we can arrange these balls in a row so that neighbouring balls are of different colours is
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The correct answer is:
$2(n !)^2$
BW BW ..... $=n ! \times n !$
or
WB WB ..... $=2(n !)^2$
or
WB WB ..... $=2(n !)^2$
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